1/128=25^x+1

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Solution for 1/128=25^x+1 equation: 



1/128=25^x+1

We move all terms to the left:

1/128-(25^x+1)=0

We get rid of parentheses

-25^x-1+1/128=0

We multiply all the terms by the denominator


-25^x*128+1-1*128=0

We add all the numbers together, and all the variables

-25^x*128-127=0

Wy multiply elements

-3200x-127=0

We move all terms containing x to the left, all other terms to the right

-3200x=127

x=127/-3200

x=-127/3200

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